What is the vertices 9x^2-36x+4y^2=0 ?

The vertices 9x^2-36x+4y^2=0 is (2,3),(2,-3)

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vertices 9x^2-36x+4y^2=0

vertices

9 x^{2} - 36 x + 4 y^{2} = 0

(2, 3), (2, - 3)

Solution steps

(h, k + b), (h, k - b)

Calculate ellipse properties

9 x^{2} - 36 x + 4 y^{2} = 0 :

Ellipse with center

(h, k) = (2, 0), b = 3, a = 2

(2, 0 + 3), (2, 0 - 3)

Refine

(2, 3), (2, - 3)

x^{2} + 4 y^{2} = 4

\frac{( x + 5 ) ^{2}}{9} + (y - 1)^{2} = 1

8 x^{2} + 2 y^{2} + 16 x = 0

9 X^{2} + 4 Y^{2} = 36

\frac{x ^{2}}{9} + \frac{y ^{2}}{5} = 1

What is the vertices 9x^2-36x+4y^2=0 ?
The vertices 9x^2-36x+4y^2=0 is (2,3),(2,-3)