What is ((x-(-1))^2)/(4^2)+((y-(-1))^2)/(3^2)=1 ?

The solution to ((x-(-1))^2)/(4^2)+((y-(-1))^2)/(3^2)=1 is Ellipse with (h,k)=(-1,-1),a=4,b=3

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((x-(-1))^2)/(4^2)+((y-(-1))^2)/(3^2)=1

\frac{( x - ( - 1 ) ) ^{2}}{4 ^{2}} + \frac{( y - ( - 1 ) ) ^{2}}{3 ^{2}} = 1

(h, k) = (- 1, - 1), a = 4, b = 3

Solution steps

\frac{( x - ( - 1 ) ) ^{2}}{4 ^{2}} + \frac{( y - ( - 1 ) ) ^{2}}{3 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (- 1, - 1), a = 4, b = 3

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (- 1, - 1), a = 4, b = 3

81 x^{2} + 9 y^{2} = 64

y^{2} + 30 x^{2} = 30

\frac{x ^{2}}{25} + \frac{( y + 3 ) ^{2}}{49} = 1

9 x^{2} + 25 y^{2} = 225

81 x^{2} - 1296 x + 16 y^{2} + 64 y = - 3952

What is ((x-(-1))^2)/(4^2)+((y-(-1))^2)/(3^2)=1 ?
The solution to ((x-(-1))^2)/(4^2)+((y-(-1))^2)/(3^2)=1 is Ellipse with (h,k)=(-1,-1),a=4,b=3