What is y^2+4x^2+24x+16y=-84 ?

The solution to y^2+4x^2+24x+16y=-84 is Ellipse with (h,k)=(-3,-8),a=2,b=4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^2+4x^2+24x+16y=-84

y^{2} + 4 x^{2} + 24 x + 16 y = - 84

(h, k) = (- 3, - 8), a = 2, b = 4

Solution steps

y^{2} + 4 x^{2} + 24 x + 16 y = - 84

Rewrite

y^{2} + 4 x^{2} + 24 x + 16 y = - 84

in the form of the standard ellipse equation

\frac{( x - ( - 3 ) ) ^{2}}{2 ^{2}} + \frac{( y - ( - 8 ) ) ^{2}}{4 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (- 3, - 8), a = 2, b = 4

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (- 3, - 8), b = 4, a = 2

\frac{y ^{2}}{10} + \frac{x ^{2}}{6} = 1

x^{2} - 8 x + 2 y^{2} + 8 y = 20

x^{2} + 36 y^{2} - 24 x - 288 y + 611 = 0

169 x^{2} + 25 y^{2} = 4225

3 x^{2} + 4 y^{2} + 28 x - 16 y + 48 = 0

What is y^2+4x^2+24x+16y=-84 ?
The solution to y^2+4x^2+24x+16y=-84 is Ellipse with (h,k)=(-3,-8),a=2,b=4