What is 14x^2+8y^2=112 ?

The solution to 14x^2+8y^2=112 is Ellipse with (h,k)=(0,0),a=2sqrt(2),b=sqrt(14)

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14x^2+8y^2=112

14 x^{2} + 8 y^{2} = 112

(h, k) = (0, 0), a = 22, b = 14

Solution steps

14 x^{2} + 8 y^{2} = 112

Rewrite

14 x^{2} + 8 y^{2} = 112

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{( 2 2 ) ^{2}} + \frac{( y - 0 ) ^{2}}{( 14 ) ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 22, b = 14

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (0, 0), b = 14, a = 22

9 y^{2} + z^{2} = 36

2 x^{2} + 8 y^{2} = 18

2 x^{2} + 8 y^{2} = 15

8 x^{2} + 4 y^{2} = 21

\frac{( x - 1 ) ^{2}}{9} + \frac{( y + 2 ) ^{2}}{16} = 1

What is 14x^2+8y^2=112 ?
The solution to 14x^2+8y^2=112 is Ellipse with (h,k)=(0,0),a=2sqrt(2),b=sqrt(14)