What is ((x+4)^2}{0.25}+\frac{(y-8)^2)/1 =1 ?

The solution to ((x+4)^2}{0.25}+\frac{(y-8)^2)/1 =1 is Ellipse with (h,k)=(-4,8),a=sqrt(0.25),b=1

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((x+4)^2}{0.25}+\frac{(y-8)^2)/1 =1

\frac{( x + 4 ) ^{2}}{0.25} + \frac{( y - 8 ) ^{2}}{1} = 1

(h, k) = (- 4, 8), a = 0.25, b = 1

Solution steps

\frac{( x + 4 ) ^{2}}{0.25} + \frac{( y - 8 ) ^{2}}{1} = 1

Rewrite

\frac{( x + 4 ) ^{2}}{0.25} + \frac{( y - 8 ) ^{2}}{1} = 1

in the form of the standard ellipse equation

\frac{( x - ( - 4 ) ) ^{2}}{( 0.25 ) ^{2}} + \frac{( y - 8 ) ^{2}}{1 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (- 4, 8), a = 0.25, b = 1

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (- 4, 8), b = 1, a = 0.25

3 x^{2} + z^{2} = 8 - x^{2} - z^{2}

- \frac{x ^{2}}{1} - \frac{y ^{2}}{4} = 1

\frac{( x + 2 ) ^{2}}{25} + \frac{( y - 3 ) ^{2}}{4} = 1

\frac{x ^{2}}{14} + \frac{y ^{2}}{6} = 1

\frac{x ^{2}}{9} + \frac{y ^{2}}{c} = 1

What is ((x+4)^2}{0.25}+\frac{(y-8)^2)/1 =1 ?
The solution to ((x+4)^2}{0.25}+\frac{(y-8)^2)/1 =1 is Ellipse with (h,k)=(-4,8),a=sqrt(0.25),b=1