What is x^2+2y^2=11 ?

The solution to x^2+2y^2=11 is Ellipse with (h,k)=(0,0),a=sqrt(11),b=sqrt(11/2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^2+2y^2=11

x^{2} + 2 y^{2} = 11

(h, k) = (0, 0), a = 11, b = \frac{11}{2}

Solution steps

x^{2} + 2 y^{2} = 11

Rewrite

x^{2} + 2 y^{2} = 11

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{( 11 ) ^{2}} + \frac{( y - 0 ) ^{2}}{( \frac{11}{2} ) ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 11, b = \frac{11}{2}

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (0, 0), a = 11, b = \frac{11}{2}

3 x^{2} + y^{2} - 5 x = 2 - y

\frac{( x - 3 ) ^{2}}{4} + \frac{( y - 3 ) ^{2}}{16} = 1

4 x^{2} + 2 y^{2} = 16

\frac{x ^{2}}{\frac{1}{2}} + y^{2} = 1

x^{2} + 4 y^{2} + 9 x + 9 y - 15 = 0

What is x^2+2y^2=11 ?
The solution to x^2+2y^2=11 is Ellipse with (h,k)=(0,0),a=sqrt(11),b=sqrt(11/2)