What is ((x-0)^2)/(2^2)+((y-0)^2)/(4^2)=1 ?

The solution to ((x-0)^2)/(2^2)+((y-0)^2)/(4^2)=1 is Ellipse with (h,k)=(0,0),a=2,b=4

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((x-0)^2)/(2^2)+((y-0)^2)/(4^2)=1

\frac{( x - 0 ) ^{2}}{2 ^{2}} + \frac{( y - 0 ) ^{2}}{4 ^{2}} = 1

(h, k) = (0, 0), a = 2, b = 4

Solution steps

\frac{( x - 0 ) ^{2}}{2 ^{2}} + \frac{( y - 0 ) ^{2}}{4 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 2, b = 4

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (0, 0), b = 4, a = 2

77 x^{2} + 81 y^{2} - 828 x - 324 y = 1944

\frac{( ( x + 1 ) ^{2} )}{9} + \frac{( ( y + 1 ) ^{2} )}{16} = 1

55 x^{2} + 5 y^{2} = 4

81 (x - 2)^{2} + 36 (y - 3)^{2} = 2916

3 x^{2} + 5 y^{2} - 6 x - 20 y + 8 = 0

What is ((x-0)^2)/(2^2)+((y-0)^2)/(4^2)=1 ?
The solution to ((x-0)^2)/(2^2)+((y-0)^2)/(4^2)=1 is Ellipse with (h,k)=(0,0),a=2,b=4