What is 2x^2-8x+y^2-6y+7=0 ?

The solution to 2x^2-8x+y^2-6y+7=0 is Ellipse with (h,k)=(2,3),a=sqrt(5),b=sqrt(10)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2x^2-8x+y^2-6y+7=0

2 x^{2} - 8 x + y^{2} - 6 y + 7 = 0

(h, k) = (2, 3), a = 5, b = 10

Solution steps

2 x^{2} - 8 x + y^{2} - 6 y + 7 = 0

Rewrite

2 x^{2} - 8 x + y^{2} - 6 y + 7 = 0

in the form of the standard ellipse equation

\frac{( x - 2 ) ^{2}}{( 5 ) ^{2}} + \frac{( y - 3 ) ^{2}}{( 10 ) ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (2, 3), a = 5, b = 10

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (2, 3), b = 10, a = 5

3 x^{2} + 2 y^{2} - 12 x + 6 y - 10 = 0

4.14 x^{2} + 3.92 y^{2} - 41.82 x - 82.62 y + 78 = 0

36 x^{2} + 8 y^{2} = 98

(\frac{y}{8})^{2} + (\frac{x}{7})^{2} = 1

\frac{x ^{2}}{64} + \frac{y ^{2}}{9} = 1

What is 2x^2-8x+y^2-6y+7=0 ?
The solution to 2x^2-8x+y^2-6y+7=0 is Ellipse with (h,k)=(2,3),a=sqrt(5),b=sqrt(10)