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Popular >

((x^2)/4)+((y^2)/(16))=1

Solution

(\frac{x ^{2}}{4}) + (\frac{y ^{2}}{16}) = 1

Solution

(h, k) = (0, 0), a = 2, b = 4

Solution steps

\frac{x ^{2}}{4} + \frac{y ^{2}}{16} = 1

Rewrite

\frac{x ^{2}}{4} + \frac{y ^{2}}{16} = 1

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{2 ^{2}} + \frac{( y - 0 ) ^{2}}{4 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 2, b = 4

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (0, 0), b = 4, a = 2

Popular Examples

25x^2+(y^2-4y)=21

25 x^{2} + (y^{2} - 4 y) = 21

(x^2)/(25)-13y+17x=-(y^2)/(49)+1

\frac{x ^{2}}{25} - 13 y + 17 x = - \frac{y ^{2}}{49} + 1

solvefor x,(Y(x)^2)/(4-x^2)=1 solve for

x, \frac{Y ( x ) ^{2}}{4 - x ^{2}} = 1

2x^2+10y^2-10x-6y-10=0

2 x^{2} + 10 y^{2} - 10 x - 6 y - 10 = 0

(y^2}{16}=1-\frac{x^2)/9

\frac{y ^{2}}{16} = 1 - \frac{x ^{2}}{9}

Frequently Asked Questions (FAQ)

What is ((x^2)/4)+((y^2)/(16))=1 ?
The solution to ((x^2)/4)+((y^2)/(16))=1 is Ellipse with (h,k)=(0,0),a=2,b=4