What is (x^2)/2+(y^2)/(16)=1 ?

The solution to (x^2)/2+(y^2)/(16)=1 is Ellipse with (h,k)=(0,0),a=sqrt(2),b=4

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(x^2)/2+(y^2)/(16)=1

\frac{x ^{2}}{2} + \frac{y ^{2}}{16} = 1

(h, k) = (0, 0), a = 2, b = 4

Solution steps

\frac{x ^{2}}{2} + \frac{y ^{2}}{16} = 1

Rewrite

\frac{x ^{2}}{2} + \frac{y ^{2}}{16} = 1

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{( 2 ) ^{2}} + \frac{( y - 0 ) ^{2}}{4 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 2, b = 4

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (0, 0), b = 4, a = 2

(\frac{x - 1}{2})^{2} + y^{2} = \frac{1}{4}

4 x^{2} + 24 y^{2} = 100

- x^{2} - 2 y^{2} = - 40

9 x^{2} + 16 y^{2} - 36 x - 64 y + (- 44) = 0

(\frac{x - 4}{6})^{2} + (\frac{y + 2}{6})^{2} = 1

What is (x^2)/2+(y^2)/(16)=1 ?
The solution to (x^2)/2+(y^2)/(16)=1 is Ellipse with (h,k)=(0,0),a=sqrt(2),b=4