3x^2+2y-3=0

Lösung

3 x^{2} + 2 y - 3 = 0

(h, k) = (0, \frac{3}{2}), p = - \frac{1}{6}

Schritte zur Lösung

3 x^{2} + 2 y - 3 = 0

Rewrite

3 x^{2} + 2 y - 3 = 0

in the standard form:

4 (- \frac{1}{6}) (y - \frac{3}{2}) = (x - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, \frac{3}{2}), p = - \frac{1}{6}

x = - \frac{1}{2} (y + 4)^{2} - 5

x^{2} + 4 x + 4 y + 20 = 0

(y - 2)^{2} = - 2 (x + 2)

3 y = 5 x^{2} + 2

x = \frac{1}{8} y^{2}