What is ((x-2)^2)/4+(y^2)/(33)=1 ?

The solution to ((x-2)^2)/4+(y^2)/(33)=1 is Ellipse with (h,k)=(2,0),a=2,b=sqrt(33)

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((x-2)^2)/4+(y^2)/(33)=1

\frac{( x - 2 ) ^{2}}{4} + \frac{y ^{2}}{33} = 1

(h, k) = (2, 0), a = 2, b = 33

Solution steps

\frac{( x - 2 ) ^{2}}{4} + \frac{y ^{2}}{33} = 1

Rewrite

\frac{( x - 2 ) ^{2}}{4} + \frac{y ^{2}}{33} = 1

in the form of the standard ellipse equation

\frac{( x - 2 ) ^{2}}{2 ^{2}} + \frac{( y - 0 ) ^{2}}{( 33 ) ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (2, 0), a = 2, b = 33

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (2, 0), b = 33, a = 2

\frac{( x + 1 ) ^{2}}{21} + \frac{( y + 5 ) ^{2}}{25} = 1

4 x^{2} + 3 y^{2} = 7

25 x^{2} + 4 y^{2} - 250 x - 16 y = - 541

x^{2} + \frac{z ^{2}}{225} = 1

4 x^{2} + 12 y^{2} - 4 x - 24 y + 1 = 0

What is ((x-2)^2)/4+(y^2)/(33)=1 ?
The solution to ((x-2)^2)/4+(y^2)/(33)=1 is Ellipse with (h,k)=(2,0),a=2,b=sqrt(33)