What is ((x-2)^2)/(4^2)+((y-3)^2)/(5^2)=1 ?

The solution to ((x-2)^2)/(4^2)+((y-3)^2)/(5^2)=1 is Ellipse with (h,k)=(2,3),a=4,b=5

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((x-2)^2)/(4^2)+((y-3)^2)/(5^2)=1

\frac{( x - 2 ) ^{2}}{4 ^{2}} + \frac{( y - 3 ) ^{2}}{5 ^{2}} = 1

(h, k) = (2, 3), a = 4, b = 5

Solution steps

\frac{( x - 2 ) ^{2}}{4 ^{2}} + \frac{( y - 3 ) ^{2}}{5 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (2, 3), a = 4, b = 5

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (2, 3), b = 5, a = 4

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y^{2} + \frac{5}{2} y + \frac{x ^{2}}{4} - 44 = 0

\frac{x ^{2}}{100} + \frac{y ^{2}}{52} = 1

\frac{( x - 14 ) ^{2}}{3} + \frac{( y - 11 ) ^{2}}{4} = 1

x^{2} + 7 y^{2} = 12

What is ((x-2)^2)/(4^2)+((y-3)^2)/(5^2)=1 ?
The solution to ((x-2)^2)/(4^2)+((y-3)^2)/(5^2)=1 is Ellipse with (h,k)=(2,3),a=4,b=5