What is (x^2)/(4^2)+(y^2)/(6^2)=1 ?

The solution to (x^2)/(4^2)+(y^2)/(6^2)=1 is Ellipse with (h,k)=(0,0),a=4,b=6

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(x^2)/(4^2)+(y^2)/(6^2)=1

\frac{x ^{2}}{4 ^{2}} + \frac{y ^{2}}{6 ^{2}} = 1

(h, k) = (0, 0), a = 4, b = 6

Solution steps

\frac{x ^{2}}{4 ^{2}} + \frac{y ^{2}}{6 ^{2}} = 1

Rewrite

\frac{x ^{2}}{4 ^{2}} + \frac{y ^{2}}{6 ^{2}} = 1

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{4 ^{2}} + \frac{( y - 0 ) ^{2}}{6 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 4, b = 6

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (0, 0), b = 6, a = 4

7 x^{2} + y^{2} = 8

9 x^{2} + 16 y^{2} - 54 x + 32 y - 47 = 0

4 x^{2} + 32 x + 9 y^{2} - 18 y + 37 = 0

x^{2} + 4 y^{2} - 6 x + 40 y + 105 = 0

x, \frac{x ^{2}}{16} + \frac{Y ( x ) ^{2}}{9} = 1

What is (x^2)/(4^2)+(y^2)/(6^2)=1 ?
The solution to (x^2)/(4^2)+(y^2)/(6^2)=1 is Ellipse with (h,k)=(0,0),a=4,b=6