What is ((x-2)^2)/9+((y+5)^2)/(16)=1 ?

The solution to ((x-2)^2)/9+((y+5)^2)/(16)=1 is Ellipse with (h,k)=(2,-5),a=3,b=4

Popular >

((x-2)^2)/9+((y+5)^2)/(16)=1

\frac{( x - 2 ) ^{2}}{9} + \frac{( y + 5 ) ^{2}}{16} = 1

(h, k) = (2, - 5), a = 3, b = 4

Solution steps

\frac{( x - 2 ) ^{2}}{9} + \frac{( y + 5 ) ^{2}}{16} = 1

Rewrite

\frac{( x - 2 ) ^{2}}{9} + \frac{( y + 5 ) ^{2}}{16} = 1

in the form of the standard ellipse equation

\frac{( x - 2 ) ^{2}}{3 ^{2}} + \frac{( y - ( - 5 ) ) ^{2}}{4 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (2, - 5), a = 3, b = 4

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (2, - 5), b = 4, a = 3

x^{2} + 8 y^{2} = 64

16 x^{2} + 4 y^{2} + 96 x - 16 y + 96 = 0

\frac{( x + 1 ) ^{2}}{49} + \frac{( y - 7 ) ^{2}}{1} = 1

4 (x - 3)^{2} + 2 (y + 4)^{2} = 16

3 x^{2} - 12 x + y^{2} - 4 y + 1 = 0

What is ((x-2)^2)/9+((y+5)^2)/(16)=1 ?
The solution to ((x-2)^2)/9+((y+5)^2)/(16)=1 is Ellipse with (h,k)=(2,-5),a=3,b=4