What is y/((x/5)^2+(y/2)^2)=1 ?

The solution to y/((x/5)^2+(y/2)^2)=1 is Ellipse with (h,k)=(0,2),a=5,b=2

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y/((x/5)^2+(y/2)^2)=1

\frac{y}{( \frac{x}{5} ) ^{2} + ( \frac{y}{2} ) ^{2}} = 1

(h, k) = (0, 2), a = 5, b = 2

Solution steps

\frac{y}{( \frac{x}{5} ) ^{2} + ( \frac{y}{2} ) ^{2}} = 1

Rewrite

\frac{y}{( \frac{x}{5} ) ^{2} + ( \frac{y}{2} ) ^{2}} = 1

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{5 ^{2}} + \frac{( y - 2 ) ^{2}}{2 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 2), a = 5, b = 2

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (0, 2), a = 5, b = 2

(\frac{X - 2}{2})^{2} + (\frac{Y + 3}{4})^{2} = 1

225 x^{2} + 289 y^{2} = 65025

(2 x^{2} + y^{2})^{2} = (3 - y)^{2}

25 x^{2} + 9 y^{2} = 25

x^{2} + 2 y^{2} - 6 x - 20 y + 59 = 12

What is y/((x/5)^2+(y/2)^2)=1 ?
The solution to y/((x/5)^2+(y/2)^2)=1 is Ellipse with (h,k)=(0,2),a=5,b=2