What is (x^2)/(8^2)+(y^2)/(7^2)=1 ?

The solution to (x^2)/(8^2)+(y^2)/(7^2)=1 is Ellipse with (h,k)=(0,0),a=8,b=7

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(x^2)/(8^2)+(y^2)/(7^2)=1

\frac{x ^{2}}{8 ^{2}} + \frac{y ^{2}}{7 ^{2}} = 1

(h, k) = (0, 0), a = 8, b = 7

Solution steps

\frac{x ^{2}}{8 ^{2}} + \frac{y ^{2}}{7 ^{2}} = 1

Rewrite

\frac{x ^{2}}{8 ^{2}} + \frac{y ^{2}}{7 ^{2}} = 1

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{8 ^{2}} + \frac{( y - 0 ) ^{2}}{7 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 8, b = 7

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (0, 0), a = 8, b = 7

\frac{x ^{2}}{25} + \frac{y ^{2}}{6 ^{2}} = 1

\frac{( X + 3 ) ^{2}}{49} + \frac{( Y + 2 ) ^{2}}{36} = 1

16 x^{2} + 25 y^{2} + 224 + 250 y - 191 = 0

\frac{( x + 3 ) ^{2}}{16} + \frac{( y + 2 ) ^{2}}{9} = 1

9 y^{2} + 36 y + 4 x^{2} = 0

What is (x^2)/(8^2)+(y^2)/(7^2)=1 ?
The solution to (x^2)/(8^2)+(y^2)/(7^2)=1 is Ellipse with (h,k)=(0,0),a=8,b=7