What is ((x-2)^2)/4+((y-1)^2)/3 =1 ?

The solution to ((x-2)^2)/4+((y-1)^2)/3 =1 is Ellipse with (h,k)=(2,1),a=2,b=sqrt(3)

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((x-2)^2)/4+((y-1)^2)/3 =1

\frac{( x - 2 ) ^{2}}{4} + \frac{( y - 1 ) ^{2}}{3} = 1

(h, k) = (2, 1), a = 2, b = 3

Solution steps

\frac{( x - 2 ) ^{2}}{4} + \frac{( y - 1 ) ^{2}}{3} = 1

Rewrite

\frac{( x - 2 ) ^{2}}{4} + \frac{( y - 1 ) ^{2}}{3} = 1

in the form of the standard ellipse equation

\frac{( x - 2 ) ^{2}}{2 ^{2}} + \frac{( y - 1 ) ^{2}}{( 3 ) ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (2, 1), a = 2, b = 3

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (2, 1), a = 2, b = 3

2 x^{2} + y^{2} = 16

4 (x - 4)^{2} + 9 (y - 2)^{2} = 36

\frac{( y + 7 ) ^{2}}{16} + \frac{( x - 5 ) ^{2}}{25} = 1

\frac{4}{x + y i} = x - y i

4 (x + 3)^{2} + y^{2} = 16

What is ((x-2)^2)/4+((y-1)^2)/3 =1 ?
The solution to ((x-2)^2)/4+((y-1)^2)/3 =1 is Ellipse with (h,k)=(2,1),a=2,b=sqrt(3)