What is (((y-8))/(40))^2+(((x+10))/(211))^2=1 ?

The solution to (((y-8))/(40))^2+(((x+10))/(211))^2=1 is Ellipse with (h,k)=(-10,8),a=211,b=40

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(((y-8))/(40))^2+(((x+10))/(211))^2=1

(\frac{( y - 8 )}{40})^{2} + (\frac{( x + 10 )}{211})^{2} = 1

(h, k) = (- 10, 8), a = 211, b = 40

Solution steps

(\frac{y - 8}{40})^{2} + (\frac{x + 10}{211})^{2} = 1

Rewrite

(\frac{y - 8}{40})^{2} + (\frac{x + 10}{211})^{2} = 1

in the form of the standard ellipse equation

\frac{( x - ( - 10 ) ) ^{2}}{21 1 ^{2}} + \frac{( y - 8 ) ^{2}}{4 0 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (- 10, 8), a = 211, b = 40

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (- 10, 8), a = 211, b = 40

1 = (\frac{x}{84.5})^{2} + (\frac{y}{33.5})^{2}

2 x^{2} + 3 y^{2} = 6

4 x^{2} + 5 y^{2} + 16 x - 20 y + 16 = 0

x^{2} + (\frac{y}{4})^{2} = 1

\frac{( x - 2 ) ^{2}}{4} + \frac{( y - 1 ) ^{2}}{3} = 1

What is (((y-8))/(40))^2+(((x+10))/(211))^2=1 ?
The solution to (((y-8))/(40))^2+(((x+10))/(211))^2=1 is Ellipse with (h,k)=(-10,8),a=211,b=40