What is -(x^2)/9-y^2=1 ?

The solution to -(x^2)/9-y^2=1 is Ellipse with (h,k)=(0,0),a=3,b=1

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-(x^2)/9-y^2=1

- \frac{x ^{2}}{9} - y^{2} = 1

(h, k) = (0, 0), a = 3, b = 1

Solution steps

- \frac{x ^{2}}{9} - y^{2} = 1

Rewrite

- \frac{x ^{2}}{9} - y^{2} = 1

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{3 ^{2}} + \frac{( y - 0 ) ^{2}}{1 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 3, b = 1

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (0, 0), a = 3, b = 1

5 x^{2} + 72 y^{2} - 2 > 0

128 + 16 y - x^{2} - 4 y^{2} \geq 0

144 y^{2} + 169 x^{2} = 169

9 (x + y i)^{2} + 9 (x - y i)^{2} + 82 (x + y i) (x - y i) = 1600

x^{2} + 4 y^{2} + 8 x - 24 y - 92 = 0

What is -(x^2)/9-y^2=1 ?
The solution to -(x^2)/9-y^2=1 is Ellipse with (h,k)=(0,0),a=3,b=1