What is (y^2)/4+z^2=1 ?

The solution to (y^2)/4+z^2=1 is Ellipse with (h,k)=(0,0),a=2,b=1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(y^2)/4+z^2=1

\frac{y ^{2}}{4} + z^{2} = 1

(h, k) = (0, 0), a = 2, b = 1

Solution steps

\frac{y ^{2}}{4} + z^{2} = 1

Rewrite

\frac{y ^{2}}{4} + z^{2} = 1

in the form of the standard ellipse equation

\frac{( y - 0 ) ^{2}}{2 ^{2}} + \frac{( z - 0 ) ^{2}}{1 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 2, b = 1

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (0, 0), a = 2, b = 1

\frac{x ^{2}}{( 1.587 ) ^{2}} + \frac{y ^{2}}{1} = 1

\frac{4}{3} x^{2} + \frac{4}{3} y^{2} = (x - 2)^{2}

9 x^{2} + 25 y^{2} + 36 x - 100 y - 89 = 0

\frac{( x - 3 ) ^{2}}{16} + \frac{( y - 3 ) ^{2}}{25} = 1

(x - 3)^{2} + (\frac{y}{4})^{2} = 1

What is (y^2)/4+z^2=1 ?
The solution to (y^2)/4+z^2=1 is Ellipse with (h,k)=(0,0),a=2,b=1