What is ((x)^2)/(25)+((y)^2)/(16)=1 ?

The solution to ((x)^2)/(25)+((y)^2)/(16)=1 is Ellipse with (h,k)=(0,0),a=5,b=4

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((x)^2)/(25)+((y)^2)/(16)=1

\frac{( x ) ^{2}}{25} + \frac{( y ) ^{2}}{16} = 1

(h, k) = (0, 0), a = 5, b = 4

Solution steps

\frac{x ^{2}}{25} + \frac{y ^{2}}{16} = 1

Rewrite

\frac{x ^{2}}{25} + \frac{y ^{2}}{16} = 1

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{5 ^{2}} + \frac{( y - 0 ) ^{2}}{4 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 5, b = 4

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (0, 0), a = 5, b = 4

\frac{x ^{2}}{256} + \frac{y ^{2}}{400} = 2

3 x^{2} + 4 y^{2} + 6 x - 24 y + 27 = 0

25 x^{2} + 9 y^{2} - 100 x + 18 x - 10 y - 31 = 0

- X^{2} - 4 = Y^{2}

8 y^{2} = - \frac{9}{2} x^{2} + \frac{25}{2}

What is ((x)^2)/(25)+((y)^2)/(16)=1 ?
The solution to ((x)^2)/(25)+((y)^2)/(16)=1 is Ellipse with (h,k)=(0,0),a=5,b=4