What is 4x^2+4y^2+16y=0 ?

The solution to 4x^2+4y^2+16y=0 is Ellipse with (h,k)=(0,-2),a=2,b=2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

4x^2+4y^2+16y=0

4 x^{2} + 4 y^{2} + 16 y = 0

(h, k) = (0, - 2), a = 2, b = 2

Solution steps

4 x^{2} + 4 y^{2} + 16 y = 0

Rewrite

4 x^{2} + 4 y^{2} + 16 y = 0

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{2 ^{2}} + \frac{( y - ( - 2 ) ) ^{2}}{2 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, - 2), a = 2, b = 2

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (0, - 2), b = 2, a = 2

9 (x - 6)^{2} + 64 (y - 4)^{2} = 576

6 x + 3 y \cdot 2 = 4 + 2 x^{2} + 5 y^{2}

\frac{( x + 2 ) ^{2}}{9} + \frac{( y - 4 ) ^{2}}{16} = 1

25 x^{2} + 64 y^{2} = 1600

\frac{( x + 4 ) ^{2}}{9} + \frac{( y - 6 ) ^{2}}{25} = 1

What is 4x^2+4y^2+16y=0 ?
The solution to 4x^2+4y^2+16y=0 is Ellipse with (h,k)=(0,-2),a=2,b=2