What is -f(x)=3(x)^2+2(x)-4 ?

The solution to -f(x)=3(x)^2+2(x)-4 is Parabola with (h,k)=(-1/3 , 13/3),p=-1/12

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-f(x)=3(x)^2+2(x)-4

- f (x) = 3 (x)^{2} + 2 (x) - 4

(h, k) = (- \frac{1}{3}, \frac{13}{3}), p = - \frac{1}{12}

Solution steps

- y = 3 x^{2} + 2 x - 4

Rewrite

- y = 3 x^{2} + 2 x - 4

in the standard form

4 (- \frac{1}{12}) (y - \frac{13}{3}) = (x - (- \frac{1}{3}))^{2}

Therefore parabola properties are:

(h, k) = (- \frac{1}{3}, \frac{13}{3}), p = - \frac{1}{12}

(x + 2)^{2} = - 8 (y + 5)

x^{2} - 6 x - 16 y - 39 = 0

x^{2} - 2 x - 4 y + 13 = 0

(y + 3)^{2} = 4 (x + 1)

(y - 1)^{2} = 2 (x + 1)

What is -f(x)=3(x)^2+2(x)-4 ?
The solution to -f(x)=3(x)^2+2(x)-4 is Parabola with (h,k)=(-1/3 , 13/3),p=-1/12