What is 9y^2+z^2=16 ?

The solution to 9y^2+z^2=16 is Ellipse with (h,k)=(0,0),a= 4/3 ,b=4

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9y^2+z^2=16

9 y^{2} + z^{2} = 16

(h, k) = (0, 0), a = \frac{4}{3}, b = 4

Solution steps

9 y^{2} + z^{2} = 16

Rewrite

9 y^{2} + z^{2} = 16

in the form of the standard ellipse equation

\frac{( y - 0 ) ^{2}}{( \frac{4}{3} ) ^{2}} + \frac{( z - 0 ) ^{2}}{4 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = \frac{4}{3}, b = 4

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (0, 0), b = 4, a = \frac{4}{3}

\frac{x ^{2}}{2.8 9 ^{2}} + \frac{y ^{2}}{2.8 4 ^{2}} = 1

(x - 2)^{2} + \frac{( y - 2 ) ^{2}}{4} = 1

\frac{( x + 2 ) ^{2}}{16} + \frac{( y - 5 ) ^{2}}{4} = 1

(\frac{y - ( - 2 )}{x - 3}) (\frac{y - 1}{x - ( - 2 )}) = - 6

x^{2} + 9 y^{2} - 14 x + 36 y + 49 = 0

What is 9y^2+z^2=16 ?
The solution to 9y^2+z^2=16 is Ellipse with (h,k)=(0,0),a= 4/3 ,b=4