What is (y^2)/4+(z^2)/9 =1 ?

The solution to (y^2)/4+(z^2)/9 =1 is Ellipse with (h,k)=(0,0),a=2,b=3

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(y^2)/4+(z^2)/9 =1

\frac{y ^{2}}{4} + \frac{z ^{2}}{9} = 1

(h, k) = (0, 0), a = 2, b = 3

Solution steps

\frac{y ^{2}}{4} + \frac{z ^{2}}{9} = 1

Rewrite

\frac{y ^{2}}{4} + \frac{z ^{2}}{9} = 1

in the form of the standard ellipse equation

\frac{( y - 0 ) ^{2}}{2 ^{2}} + \frac{( z - 0 ) ^{2}}{3 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 2, b = 3

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (0, 0), b = 3, a = 2

2 x^{2} + y^{2} - 2 x \leq 0

\frac{( x + 7 ) ^{2}}{6} + \frac{( y + 7 ) ^{2}}{5} = 1

4 x^{2} - 16 + y^{2} + 2 y = - 1

9 x^{2} + 49 y^{2} = 1

8 x^{2} + 18 y^{2} + 32 x - 36 y - 22 = 0

What is (y^2)/4+(z^2)/9 =1 ?
The solution to (y^2)/4+(z^2)/9 =1 is Ellipse with (h,k)=(0,0),a=2,b=3