What is ((x-1)^2)/(3^2)+((y+3)^2)/(5^2)=1 ?

The solution to ((x-1)^2)/(3^2)+((y+3)^2)/(5^2)=1 is Ellipse with (h,k)=(1,-3),a=3,b=5

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((x-1)^2)/(3^2)+((y+3)^2)/(5^2)=1

\frac{( x - 1 ) ^{2}}{3 ^{2}} + \frac{( y + 3 ) ^{2}}{5 ^{2}} = 1

(h, k) = (1, - 3), a = 3, b = 5

Solution steps

\frac{( x - 1 ) ^{2}}{3 ^{2}} + \frac{( y + 3 ) ^{2}}{5 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (1, - 3), a = 3, b = 5

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (1, - 3), b = 5, a = 3

4 x^{2} + z^{2} = 36

\frac{x ^{2}}{4} + \frac{y ^{2}}{9} = 1 (2)

16 x^{2} + 4 y^{2} = 49

4 x^{2} + 8 y^{2} - 16 = 0

17 x^{2} + 10 y^{2} + 102 x + 80 y + 143 = 0

What is ((x-1)^2)/(3^2)+((y+3)^2)/(5^2)=1 ?
The solution to ((x-1)^2)/(3^2)+((y+3)^2)/(5^2)=1 is Ellipse with (h,k)=(1,-3),a=3,b=5