What is (x^2)/3+(y^2)/6 =1 ?

The solution to (x^2)/3+(y^2)/6 =1 is Ellipse with (h,k)=(0,0),a=sqrt(3),b=sqrt(6)

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(x^2)/3+(y^2)/6 =1

\frac{x ^{2}}{3} + \frac{y ^{2}}{6} = 1

(h, k) = (0, 0), a = 3, b = 6

Solution steps

\frac{x ^{2}}{3} + \frac{y ^{2}}{6} = 1

Rewrite

\frac{x ^{2}}{3} + \frac{y ^{2}}{6} = 1

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{( 3 ) ^{2}} + \frac{( y - 0 ) ^{2}}{( 6 ) ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 3, b = 6

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (0, 0), b = 6, a = 3

(x - 5)^{2} + \frac{y ^{2}}{25} = 1

\frac{( x - 2 ) ^{2}}{3 ^{2}} + \frac{( y - 1 ) ^{2}}{2 ^{2}} = 1

\frac{( x ^{2} )}{9} + \frac{( y ^{2} )}{16} = 1

(\frac{x ^{2}}{64}) + (\frac{y ^{2}}{25}) = 1

1^{2} = (X - 0)^{2} + (Y - 1)^{2}

What is (x^2)/3+(y^2)/6 =1 ?
The solution to (x^2)/3+(y^2)/6 =1 is Ellipse with (h,k)=(0,0),a=sqrt(3),b=sqrt(6)