What is (y-6)^2+8x^2=64 ?

The solution to (y-6)^2+8x^2=64 is Ellipse with (h,k)=(0,6),a=2sqrt(2),b=8

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(y-6)^2+8x^2=64

(y - 6)^{2} + 8 x^{2} = 64

(h, k) = (0, 6), a = 22, b = 8

Solution steps

(y - 6)^{2} + 8 x^{2} = 64

Rewrite

(y - 6)^{2} + 8 x^{2} = 64

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{( 2 2 ) ^{2}} + \frac{( y - 6 ) ^{2}}{8 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 6), a = 22, b = 8

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (0, 6), b = 8, a = 22

x^{2} + 16 y^{2} - 128 y + 240 = 0

4 x^{2} + y^{2} = 6 y - 5

18 x^{2} + 12 y^{2} + 24 x - 12 y = 1

16 x^{2} + 25 y^{2} + 32 x - 150 y - 159 = 0

(x - 1)^{2} = 4 - 2 (y + 5)^{2}

What is (y-6)^2+8x^2=64 ?
The solution to (y-6)^2+8x^2=64 is Ellipse with (h,k)=(0,6),a=2sqrt(2),b=8