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Popular >

4x^2+y^2-16x+2y+1=0

Solution

4 x^{2} + y^{2} - 16 x + 2 y + 1 = 0

Solution

(h, k) = (2, - 1), a = 2, b = 4

Solution steps

4 x^{2} + y^{2} - 16 x + 2 y + 1 = 0

Rewrite

4 x^{2} + y^{2} - 16 x + 2 y + 1 = 0

in the form of the standard ellipse equation

\frac{( x - 2 ) ^{2}}{2 ^{2}} + \frac{( y - ( - 1 ) ) ^{2}}{4 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (2, - 1), a = 2, b = 4

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (2, - 1), b = 4, a = 2

Popular Examples

((x-3)^2)/(25)+((y-4)^2)/(36)=1

\frac{( x - 3 ) ^{2}}{25} + \frac{( y - 4 ) ^{2}}{36} = 1

2x^2+y^2+16x-4y+32=0

2 x^{2} + y^{2} + 16 x - 4 y + 32 = 0

((x-5)^2}{16}+\frac{(y-3)^2)/4 =1

\frac{( x - 5 ) ^{2}}{16} + \frac{( y - 3 ) ^{2}}{4} = 1

4y^2-338x+32y=-169x^2+443

4 y^{2} - 338 x + 32 y = - 169 x^{2} + 443

2x^2+y^2-4x+8y-4=0

2 x^{2} + y^{2} - 4 x + 8 y - 4 = 0

Frequently Asked Questions (FAQ)

What is 4x^2+y^2-16x+2y+1=0 ?
The solution to 4x^2+y^2-16x+2y+1=0 is Ellipse with (h,k)=(2,-1),a=2,b=4