What is ((x-0.31))/(1.9)+(y^2)/(4.09)=2 ?

The solution to ((x-0.31))/(1.9)+(y^2)/(4.09)=2 is Parabola with (h,k)=(4.11,0),p=-0.53815…

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

((x-0.31))/(1.9)+(y^2)/(4.09)=2

\frac{( x - 0.31 )}{1.9} + \frac{y ^{2}}{4.09} = 2

(h, k) = (4.11, 0), p = - 0.53815 \dots

Solution steps

\frac{x - 0.31}{1.9} + \frac{y ^{2}}{4.09} = 2

Rewrite

\frac{x - 0.31}{1.9} + \frac{y ^{2}}{4.09} = 2

in the standard form:

4 (- 0.53815 \dots) (x - 4.11) = (y - 0)^{2}

Therefore parabola properties are:

(h, k) = (4.11, 0), p = - 0.53815 \dots

y^{2} - 12 x + 36 = 0

y^{2} = - \frac{1}{3} x

x^{2} + 12 x + \frac{3}{2} y + 39 = 0

x^{2} + y - 25 = 0

x = 4 y - y^{2}

What is ((x-0.31))/(1.9)+(y^2)/(4.09)=2 ?
The solution to ((x-0.31))/(1.9)+(y^2)/(4.09)=2 is Parabola with (h,k)=(4.11,0),p=-0.53815…