What is (x^2)/(7^2)+(y^2)/(3^2)=1 ?

The solution to (x^2)/(7^2)+(y^2)/(3^2)=1 is Ellipse with (h,k)=(0,0),a=7,b=3

Popular >

(x^2)/(7^2)+(y^2)/(3^2)=1

\frac{x ^{2}}{7 ^{2}} + \frac{y ^{2}}{3 ^{2}} = 1

(h, k) = (0, 0), a = 7, b = 3

Solution steps

\frac{x ^{2}}{7 ^{2}} + \frac{y ^{2}}{3 ^{2}} = 1

Rewrite

\frac{x ^{2}}{7 ^{2}} + \frac{y ^{2}}{3 ^{2}} = 1

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{7 ^{2}} + \frac{( y - 0 ) ^{2}}{3 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 7, b = 3

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (0, 0), a = 7, b = 3

16 x^{2} + 25 y^{2} - 64 x + 150 y = - 279

4 x^{2} + y^{2} - 40 x + 4 y + 68 = 0

x^{2} + 2 x = - 4 y^{2} + 12 y + 7

x^{2} + 3 y^{2} + 10 x + 9 y - 20 = 0

\frac{( x + 1 ) ^{2}}{32} + \frac{( y + 5 ) ^{2}}{36} = 1

What is (x^2)/(7^2)+(y^2)/(3^2)=1 ?
The solution to (x^2)/(7^2)+(y^2)/(3^2)=1 is Ellipse with (h,k)=(0,0),a=7,b=3