What is ((x-1)^2)/9+((y-2)^2)/4 =1 ?

The solution to ((x-1)^2)/9+((y-2)^2)/4 =1 is Ellipse with (h,k)=(1,2),a=3,b=2

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((x-1)^2)/9+((y-2)^2)/4 =1

\frac{( x - 1 ) ^{2}}{9} + \frac{( y - 2 ) ^{2}}{4} = 1

(h, k) = (1, 2), a = 3, b = 2

Solution steps

\frac{( x - 1 ) ^{2}}{9} + \frac{( y - 2 ) ^{2}}{4} = 1

Rewrite

\frac{( x - 1 ) ^{2}}{9} + \frac{( y - 2 ) ^{2}}{4} = 1

in the form of the standard ellipse equation

\frac{( x - 1 ) ^{2}}{3 ^{2}} + \frac{( y - 2 ) ^{2}}{2 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (1, 2), a = 3, b = 2

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (1, 2), a = 3, b = 2

25 x^{2} + 12 y^{2} + 20 x - 12 y = 4

9 x^{2} + 4 y^{2} - 18 x + 24 y + 9 = 0

(\frac{( x + 3 )}{16})^{2} + \frac{( y - 5 ) ^{2}}{25} = 1

- 4 x^{2} - 7 y^{2} > - 28

\frac{1}{4} (x - 2)^{2} + \frac{1}{16} (y + 7)^{2} = 1

What is ((x-1)^2)/9+((y-2)^2)/4 =1 ?
The solution to ((x-1)^2)/9+((y-2)^2)/4 =1 is Ellipse with (h,k)=(1,2),a=3,b=2