What is 2x^2+y^2+12x-2y+17=0 ?

The solution to 2x^2+y^2+12x-2y+17=0 is Ellipse with (h,k)=(-3,1),a=1,b=sqrt(2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2x^2+y^2+12x-2y+17=0

2 x^{2} + y^{2} + 12 x - 2 y + 17 = 0

(h, k) = (- 3, 1), a = 1, b = 2

Solution steps

2 x^{2} + y^{2} + 12 x - 2 y + 17 = 0

Rewrite

2 x^{2} + y^{2} + 12 x - 2 y + 17 = 0

in the form of the standard ellipse equation

\frac{( x - ( - 3 ) ) ^{2}}{1 ^{2}} + \frac{( y - 1 ) ^{2}}{( 2 ) ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (- 3, 1), a = 1, b = 2

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (- 3, 1), b = 2, a = 1

y^{2} + 2 y + 6 x^{2} - 12 x = 1

x^{2} + 2 y^{2} - 2 x - 4 y - 5 = 0

x^{2} + 9 y^{2} + 90 y + 189 = 0

4 x^{2} + 36 y^{2} = 144

2 x - x^{2} - 4 y^{2} - 16 y - 1 \geq 0

What is 2x^2+y^2+12x-2y+17=0 ?
The solution to 2x^2+y^2+12x-2y+17=0 is Ellipse with (h,k)=(-3,1),a=1,b=sqrt(2)