What is 9x^2+49y^2=441 ?

The solution to 9x^2+49y^2=441 is Ellipse with (h,k)=(0,0),a=7,b=3

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9x^2+49y^2=441

9 x^{2} + 49 y^{2} = 441

(h, k) = (0, 0), a = 7, b = 3

Solution steps

9 x^{2} + 49 y^{2} = 441

Rewrite

9 x^{2} + 49 y^{2} = 441

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{7 ^{2}} + \frac{( y - 0 ) ^{2}}{3 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 7, b = 3

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (0, 0), a = 7, b = 3

\frac{x ^{2}}{81} + \frac{y ^{2}}{16} = 1

\frac{x ^{2}}{8} + \frac{y ^{2}}{4} = 1

\frac{x ^{2}}{36} + \frac{y ^{2}}{11} = 1

9 x^{2} + 16 y^{2} + 96 y = 0

\frac{( x - 4 ) ^{2}}{4} + \frac{( y - 3 ) ^{2}}{9} = 1

What is 9x^2+49y^2=441 ?
The solution to 9x^2+49y^2=441 is Ellipse with (h,k)=(0,0),a=7,b=3