What is ((x-1)^2}{16}+\frac{(y-2)^2)/4 =1 ?

The solution to ((x-1)^2}{16}+\frac{(y-2)^2)/4 =1 is Ellipse with (h,k)=(1,2),a=4,b=2

Popular >

((x-1)^2}{16}+\frac{(y-2)^2)/4 =1

\frac{( x - 1 ) ^{2}}{16} + \frac{( y - 2 ) ^{2}}{4} = 1

(h, k) = (1, 2), a = 4, b = 2

Solution steps

\frac{( x - 1 ) ^{2}}{16} + \frac{( y - 2 ) ^{2}}{4} = 1

Rewrite

\frac{( x - 1 ) ^{2}}{16} + \frac{( y - 2 ) ^{2}}{4} = 1

in the form of the standard ellipse equation

\frac{( x - 1 ) ^{2}}{4 ^{2}} + \frac{( y - 2 ) ^{2}}{2 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (1, 2), a = 4, b = 2

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (1, 2), a = 4, b = 2

x^{2} + 4 y^{2} - 4 x - 8 y - 92 = 0

\frac{x ^{2}}{5 ^{2}} + \frac{y ^{2}}{4 ^{2}} = 1

\frac{( x - 2 ) ^{2}}{16} + \frac{( y + 3 ) ^{2}}{9} = 1

7 x^{2} + 16 y^{2} = 112

2 x^{2} + 10 y^{2} + 10 x - 6 y - 10 = 0

What is ((x-1)^2}{16}+\frac{(y-2)^2)/4 =1 ?
The solution to ((x-1)^2}{16}+\frac{(y-2)^2)/4 =1 is Ellipse with (h,k)=(1,2),a=4,b=2