What is (x^2)/(5^2)+(y^2)/(4^2)=1 ?

The solution to (x^2)/(5^2)+(y^2)/(4^2)=1 is Ellipse with (h,k)=(0,0),a=5,b=4

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(x^2)/(5^2)+(y^2)/(4^2)=1

\frac{x ^{2}}{5 ^{2}} + \frac{y ^{2}}{4 ^{2}} = 1

(h, k) = (0, 0), a = 5, b = 4

Solution steps

\frac{x ^{2}}{5 ^{2}} + \frac{y ^{2}}{4 ^{2}} = 1

Rewrite

\frac{x ^{2}}{5 ^{2}} + \frac{y ^{2}}{4 ^{2}} = 1

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{5 ^{2}} + \frac{( y - 0 ) ^{2}}{4 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 5, b = 4

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (0, 0), a = 5, b = 4

\frac{( x - 2 ) ^{2}}{16} + \frac{( y + 3 ) ^{2}}{9} = 1

7 x^{2} + 16 y^{2} = 112

2 x^{2} + 10 y^{2} + 10 x - 6 y - 10 = 0

x^{2} + y^{2} - 4 y \leq 0

\frac{x ^{2}}{16} + \frac{( y + 4 ) ^{2}}{81} = 1

What is (x^2)/(5^2)+(y^2)/(4^2)=1 ?
The solution to (x^2)/(5^2)+(y^2)/(4^2)=1 is Ellipse with (h,k)=(0,0),a=5,b=4