What is the diameter x^2+y^2-18x-14y+124=0 ?

The diameter x^2+y^2-18x-14y+124=0 is d=2sqrt(6)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

diameter x^2+y^2-18x-14y+124=0

diameter

x^{2} + y^{2} - 18 x - 14 y + 124 = 0

d = 26

Solution steps

d = 2 r

Find the radius

Radius given

x^{2} + y^{2} - 18 x - 14 y + 124 = 0 : r = 6

d = 26

x^{2} + y^{2} \leq 1

x^{2} + y^{2} + 6 x - 47 = 387

x^{2} + y^{2} - 4 x - 2 y - 36 = 0

x^{2} + y^{2} - 14 x + 8 y - 16 = 0

(x - 3)^{2} + (y + 3)^{2} = 6^{2}

What is the diameter x^2+y^2-18x-14y+124=0 ?
The diameter x^2+y^2-18x-14y+124=0 is d=2sqrt(6)