What is the circumference (x+2)^2+(y-1)^2=25 ?

The circumference (x+2)^2+(y-1)^2=25 is C=10pi

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circumference (x+2)^2+(y-1)^2=25

circumference

(x + 2)^{2} + (y - 1)^{2} = 25

C = 10 π

Solution steps

C = 2 π r

Find the radius

Radius given

(x + 2)^{2} + (y - 1)^{2} = 25 : r = 5

C = 2 π 5

Refine

C = 10 π

x^{2} + (y - 3)^{2} = 20

x^{2} - 3 x + 4 y + y^{2} = 16

x^{2} + y^{2} + 4 x + 12 y + 3 = 0

9 x^{2} + 9 y^{2} - 6 x - 2 y - 11 = 0

x^{2} + y^{2} - 6 x - 8 y - 3 = 0

What is the circumference (x+2)^2+(y-1)^2=25 ?
The circumference (x+2)^2+(y-1)^2=25 is C=10pi