What is the circumference 9x^2+9y^2-6x-2y-11=0 ?

The circumference 9x^2+9y^2-6x-2y-11=0 is C=(2sqrt(109)pi)/9

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circumference 9x^2+9y^2-6x-2y-11=0

circumference

9 x^{2} + 9 y^{2} - 6 x - 2 y - 11 = 0

C = \frac{2 109 π}{9}

Solution steps

C = 2 π r

Find the radius

Radius given

9 x^{2} + 9 y^{2} - 6 x - 2 y - 11 = 0 : r = \frac{109}{9}

C = 2 π \frac{109}{9}

Refine

C = \frac{2 109 π}{9}

x^{2} + y^{2} - 6 x - 8 y - 3 = 0

4 x^{2} + 4 y^{2} - 4 x + 8 y - 11 = 0

x^{2} + y^{2} + 5 x + 20 y + 10 = 0

x^{2} + y^{2} + 2 x + 6 y - 104 = 0

(x - \frac{1}{2})^{2} + (y - \frac{3}{2})^{2} = 1

What is the circumference 9x^2+9y^2-6x-2y-11=0 ?
The circumference 9x^2+9y^2-6x-2y-11=0 is C=(2sqrt(109)pi)/9