What is the circumference x^2+y^2-8x+6y+16=0 ?

The circumference x^2+y^2-8x+6y+16=0 is C=6pi

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circumference x^2+y^2-8x+6y+16=0

circumference

x^{2} + y^{2} - 8 x + 6 y + 16 = 0

C = 6 π

Solution steps

C = 2 π r

Find the radius

Radius given

x^{2} + y^{2} - 8 x + 6 y + 16 = 0 : r = 3

C = 2 π 3

Refine

C = 6 π

(x - 4)^{2} + (y + 3)^{2} = 9

(x - 2.33)^{2} + (y - 1.5)^{2} = 17

x^{2} + y^{2} - 6 x + 2 y - 15 = 0

(x + 4)^{2} + (y - 1)^{2} = 25

x^{2} + y^{2} - 6 y - 7 = 0

What is the circumference x^2+y^2-8x+6y+16=0 ?
The circumference x^2+y^2-8x+6y+16=0 is C=6pi