What is the circumference x^2+y^2-6x+2y-15=0 ?

The circumference x^2+y^2-6x+2y-15=0 is C=10pi

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

circumference x^2+y^2-6x+2y-15=0

circumference

x^{2} + y^{2} - 6 x + 2 y - 15 = 0

C = 10 π

Solution steps

C = 2 π r

Find the radius

Radius given

x^{2} + y^{2} - 6 x + 2 y - 15 = 0 : r = 5

C = 2 π 5

Refine

C = 10 π

(x + 4)^{2} + (y - 1)^{2} = 25

x^{2} + y^{2} - 6 y - 7 = 0

x^{2} + y^{2} + 6 x + 4 y + 4 = 0

(x - 0.5)^{2} + (y - 3.5)^{2} = 4

x^{2} + y^{2} - 2 x = 0

What is the circumference x^2+y^2-6x+2y-15=0 ?
The circumference x^2+y^2-6x+2y-15=0 is C=10pi