What is the circumference 4x^2+4y^2+12x-4y-88=0 ?

The circumference 4x^2+4y^2+12x-4y-88=0 is C=7sqrt(2)pi

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circumference 4x^2+4y^2+12x-4y-88=0

circumference

4 x^{2} + 4 y^{2} + 12 x - 4 y - 88 = 0

C = 72 π

Solution steps

C = 2 π r

Find the radius

Radius given

4 x^{2} + 4 y^{2} + 12 x - 4 y - 88 = 0 : r = \frac{7}{2}

C = 2 π \frac{7}{2}

Refine

C = 72 π

x^{2} - 4 x + y^{2} + 2 y + 1 = 0

x^{2} - 6 x + y^{2} + 4 y + 4 = 0

x^{2} + y^{2} - 2 x + 6 y - 15 = 0

x^{2} + y^{2} - 10 x - 6 y + 25 = 0

(x - 3)^{2} + (y - 2)^{2} = 2

What is the circumference 4x^2+4y^2+12x-4y-88=0 ?
The circumference 4x^2+4y^2+12x-4y-88=0 is C=7sqrt(2)pi