What is the circumference 2x^2+2y^2+10x-6y+3=0 ?

The circumference 2x^2+2y^2+10x-6y+3=0 is C=2sqrt(7)pi

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circumference 2x^2+2y^2+10x-6y+3=0

circumference

2 x^{2} + 2 y^{2} + 10 x - 6 y + 3 = 0

C = 27 π

Solution steps

C = 2 π r

Find the radius

Radius given

2 x^{2} + 2 y^{2} + 10 x - 6 y + 3 = 0 : r = 7

C = 27 π

4 x^{2} + 4 y^{2} + 12 x - 4 y - 88 = 0

x^{2} - 4 x + y^{2} + 2 y + 1 = 0

x^{2} - 6 x + y^{2} + 4 y + 4 = 0

x^{2} + y^{2} - 2 x + 6 y - 15 = 0

x^{2} + y^{2} - 10 x - 6 y + 25 = 0

What is the circumference 2x^2+2y^2+10x-6y+3=0 ?
The circumference 2x^2+2y^2+10x-6y+3=0 is C=2sqrt(7)pi