What is the circumference 9x^2+9y^2+18x-18y+14=0 ?

The circumference 9x^2+9y^2+18x-18y+14=0 is C=(4pi)/3

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circumference 9x^2+9y^2+18x-18y+14=0

circumference

9 x^{2} + 9 y^{2} + 18 x - 18 y + 14 = 0

C = \frac{4 π}{3}

Solution steps

C = 2 π r

Find the radius

Radius given

9 x^{2} + 9 y^{2} + 18 x - 18 y + 14 = 0 : r = \frac{2}{3}

C = 2 π \frac{2}{3}

Refine

C = \frac{4 π}{3}

(x - 3)^{2} + (y - 2)^{2} = 9

(x - 3)^{2} + (y - 2)^{2} = 4

c i rc l e, f in d C i rc u m f ere n ce, g i v e n r = 8

x^{2} + y^{2} - 6 x + 8 y + 20 = 0

x^{2} + 8 x - 6 y + y^{2} - 11 = 0

What is the circumference 9x^2+9y^2+18x-18y+14=0 ?
The circumference 9x^2+9y^2+18x-18y+14=0 is C=(4pi)/3