What is the radius 364+28y+y^2+x^2=-26x ?

The radius 364+28y+y^2+x^2=-26x is r=1

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radius 364+28y+y^2+x^2=-26x

radius

364 + 28 y + y^{2} + x^{2} = - 26 x

r = 1

Solution steps

364 + 28 y + y^{2} + x^{2} = - 26 x

Rewrite

364 + 28 y + y^{2} + x^{2} = - 26 x

in the form of the standard circle equation

(x - (- 13))^{2} + (y - (- 14))^{2} = 1^{2}

Therefore the circle properties are:

(a, b) = (- 13, - 14), r = 1

And the radius is:

r = 1

(x - 6)^{2} + (y - 4)^{2} = 25

x^{2} + y^{2} + 6 x - 2 y - 8 = 0

x^{2} + y^{2} + 2 x + 4 y - 20 = 0

(x - 2)^{2} + (y - 5)^{2} = 9

x^{2} + y^{2} - 8 = 0

What is the radius 364+28y+y^2+x^2=-26x ?
The radius 364+28y+y^2+x^2=-26x is r=1