What is the radius 3(x-5)^2+3y^2=27 ?

The radius 3(x-5)^2+3y^2=27 is r=3

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radius 3(x-5)^2+3y^2=27

radius

3 (x - 5)^{2} + 3 y^{2} = 27

r = 3

Solution steps

3 (x - 5)^{2} + 3 y^{2} = 27

Rewrite

3 (x - 5)^{2} + 3 y^{2} = 27

in the form of the standard circle equation

(x - 5)^{2} + (y - 0)^{2} = 3^{2}

Therefore the circle properties are:

(a, b) = (5, 0), r = 3

And the radius is:

r = 3

x^{2} + y^{2} + 12 y = - 32

(x - 1)^{2} + (y + 3)^{2} - 9 = 0

(x + 2)^{2} + (y - 4)^{2} = 9

x^{2} + y^{2} - 4 x - 6 y - 23 = 0

(x - 1)^{2} + (y - 3)^{2} = 16