What is the radius x^2+y^2+12y=-32 ?

The radius x^2+y^2+12y=-32 is r=2

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radius x^2+y^2+12y=-32

radius

x^{2} + y^{2} + 12 y = - 32

r = 2

Solution steps

x^{2} + y^{2} + 12 y = - 32

Rewrite

x^{2} + y^{2} + 12 y = - 32

in the form of the standard circle equation

(x - 0)^{2} + (y - (- 6))^{2} = 2^{2}

Therefore the circle properties are:

(a, b) = (0, - 6), r = 2

And the radius is:

r = 2

(x - 1)^{2} + (y + 3)^{2} - 9 = 0

(x + 2)^{2} + (y - 4)^{2} = 9

x^{2} + y^{2} - 4 x - 6 y - 23 = 0

(x - 1)^{2} + (y - 3)^{2} = 16

x^{2} + y^{2} - 2 y - 15 = 0