What is the radius x^2+(y-4)^2=4 ?

The radius x^2+(y-4)^2=4 is r=2

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radius x^2+(y-4)^2=4

radius

x^{2} + (y - 4)^{2} = 4

r = 2

Solution steps

x^{2} + (y - 4)^{2} = 4

Rewrite

x^{2} + (y - 4)^{2} = 4

in the form of the standard circle equation

(x - 0)^{2} + (y - 4)^{2} = 2^{2}

Therefore the circle properties are:

(a, b) = (0, 4), r = 2

And the radius is:

r = 2

x^{2} + y^{2} + 9 x - 9 y - 17 = 0

x^{2} + y^{2} + 6 x + 8 y + 24 = 0

x^{2} + y^{2} + 8 x - 6 y = 6

x^{2} + y^{2} - 8 x + 8 = 0

(x + 2)^{2} + (y - 4)^{2} = 25