What is the radius (x+2)^2+(y+5)^2=16 ?

The radius (x+2)^2+(y+5)^2=16 is r=4

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radius (x+2)^2+(y+5)^2=16

radius

(x + 2)^{2} + (y + 5)^{2} = 16

r = 4

Solution steps

(x + 2)^{2} + (y + 5)^{2} = 16

Rewrite

(x + 2)^{2} + (y + 5)^{2} = 16

in the form of the standard circle equation

(x - (- 2))^{2} + (y - (- 5))^{2} = 4^{2}

Therefore the circle properties are:

(a, b) = (- 2, - 5), r = 4

And the radius is:

r = 4

x^{2} + y^{2} + 7 x - 4 y - 2 = 0

y^{2} + x^{2} = 25

x^{2} + y^{2} - 14 x - 12 y + 59 = 0

(x + 5)^{2} + (y - 2)^{2} = 25

x^{2} + (y - 4)^{2} = 1